Comments on: Awk Print Line After A Matching /regex/

By: royi

royi — Sat, 07 Jan 2012 00:15:08 +0000

awk -F “=” ‘{if ($1 like “abc”) print $2 }’

By: paddu

paddu — Fri, 01 Jul 2011 11:30:19 +0000

I have a line abc=xyz
i want to find a pattern “abc=” and if exist print xyz
can some one please help

By: Ajay

Ajay — Mon, 08 Jun 2009 03:12:47 +0000

You can us grep as well:
whois bbc.co.uk | grep -A 1 Registrar| grep -v Registrar

By: nyxx

nyxx — Sat, 16 May 2009 18:26:01 +0000

Reducing awk code for a while we’ll get tha same
$ whois bbc.co.uk | awk -F: '/Registrar:/ { getline; print }' British Broadcasting Corporation [Tag = BBC]

By: Julio A. Cartaya

Julio A. Cartaya — Sat, 16 May 2009 10:17:43 +0000

Simply saying:
$ awk ‘/regexp/’ /pathto/file
will do the trick: the default action in awk is printing.

By: GByte

GByte — Thu, 14 May 2009 09:15:10 +0000

How about:
$pgrep -A 1 regexp | tail -n 1
?

By: Nikhil

Nikhil — Thu, 14 May 2009 09:06:37 +0000

$0 != “” looks like a redundant check since it is still the line matching the regex and not the next line.

By: Hai Vu

Hai Vu — Wed, 13 May 2009 16:03:16 +0000

I suggest to use print instead of print $0: it is shorter.