Is there a way to add an empty line for every 5 lines of data using grep?

line1
line2
line3
line4
line5
(empty line)
line6
line7
line8
line9
line10
(empty line)

Little fix in this BASH script:

#!/bin/bash
#!/bin/sh
files=”/home/tiger/test_moduls/*.txt”
for i in $files
do
sed ‘/^ *$/d’ $i > $i.out
mv $i.out $i
done

Good Luck! :-)

I don’t if is the right to post this issue,
is there any way to dump the new insert data to a textfile with shell script, for ie. after insertion to the mysql database execute the shell script to append and append the new record?

thanks

when I run this shell script
# while IFS= read -r line; do echo “$line” | sed -e ‘s/-//g’ -e ‘s/://g’ | awk ‘{ print $1$2 ” | ” substr($0, index($0,$3))}’; done testdb1.pl;

the file output is below: the line 1 not remove and added datetimemessage, is there any way to remove the line 1 which is “datetimemessage | datetime message”

datetimemessage | datetime message
20110713134535 | Hello World of War Craft
20110713134843 | This is a Test of text

echo '2011-07-13 13:45:35 Hello World of War Craft'  | sed -e 's/-//g' -e 's/://g' | awk '{ print $1$2 " | " substr($0, index($0,$3))}'

Result:

20110713134535 | Hello World of War Craft

You need to process the file using while loop:

while IFS= read -r line
do
   echo "$line" | sed -e 's/-//g' -e 's/://g' | awk '{ print $1$2 " | " substr($0, index($0,$3))}'
done < "input.txt"

There may be a better solution to reduced awk, but I’m too lazy to try it out ;)

### original file ###
datetime message
2011-07-13 13:45:35 Hello World of War Craft
2011-07-13 13:48:43 This is a Test of text

### output file ###
20110713134535 | Hello World of War Craft
20110713134843 | This is a Test of text

thanks

grep -v “^$” * | wc -l

\w is the special regular expression for whitespace. Both the sed and grep matches should be changed to:

/^\w*$/

-Angwe

echo `wc -l * | grep total | cut -f2 -d’ ‘` – `grep -in “^$” * | wc -l ` | bc

Using the command
grep -R “SP1_125″
you can get the lines with SP1_125.
if you want to assign to a variable then use
var_a=$(grep -R “SP1_125″ )

where is the name of file

thanks,
Renz

Now I want the line which is having SP1_125 ie., line number 3 and store it in an variable
plz can any tell the answer plz
can u mail to {snip_no_email_ids}

I tried to use the command sed given above to remove blank line from my file.

The file looks good except one strange behaviour:
“Always” the last line of the file is removed..for example:
test.p is the file and following are the contents of the file:

BEFORE RUNNING THE SED COMMAND:
“this is test 1.

this is test 2.

this is test 3.”

AFTER RUNNING THE SED COMMAND:
“this is test 1.
this is test 2.”

As you can see the last line (“this is test 3.”) is removed after running the command.

If I put the blank line at the end it removes the blank line i.e.
“this is test 1.

this is test 2.

this is test 3.

”

becomes…….
“this is test 1.
this is test 2.
this is test 3.”

Do let me know what I should do in this case?

Waiting for your prompt reply…!

Thanks and Best Regards,
Prashant Deshani

This removes blank lines from input.txt

sed ‘/^$/d’ -i input.txt