UNIX / Linux Command To Check Existing Groups and Users

by Vivek Gite on June 27, 2008 · 12 comments

Q. How do I check the existing Linux / UNIX users and groups under Linux operating system?

A. You can easily check the existing users and groups under Linux using the following commands.

Find out if user exists in /etc/passwd file

/etc/passwd file stores essential information required during login. All you have to do is search this file for user name using following syntax:
$ egrep -i "^username" /etc/passwd
For, example find out if vivek user exists or not, enter:
$ egrep -i "^vivek" /etc/passwd
Sample output:

vivek:x:1000:1000:Vivek Gite,,,,:/home/vivek:/bin/bash

A quick shell script code:

#!/bin/bash
# init
USERID="$1"
#....
/bin/egrep  -i "^${USERID}" /etc/passwd
if [ $? -eq 0 ]; then
   echo "User $USERID exists in /etc/passwd"
else
   echo "User $USERID does not exists in /etc/passwd"
fi
# ....

Normally, exit status is 0 returned if user accounts (lines) are found and 1 otherwise.

Find out if group exists in /etc/group file

/etc/group is an text file which defines the groups to which users belong under Linux and UNIX operating system. Again, you have to search /etc/group file using following syntax:
$ egrep -i "^groupname" /etc/group
For, example find out if vivek group exists or not, enter:
$ egrep -i "^vivek" /etc/group

id command

id is another command to display user / group information for any USERNAME, or the current user. To find out more about user called, tom, enter:
$ id tom
Sample output

id: tom: No such user

To find out ftpuser group, enter:
$ id -g ftpuser
Sample output:

id: ftpuser: No such user

id command exit status is 0 returned if user accounts (lines) are found and 1 otherwise. A sample shell script using id command:

#!/bin/bash
USERID="$1"
/bin/id $USERID 2>/dev/null
[ $? -eq 0 ] && echo "User found" || echo "User not found"
 
/bin/id -g $USERID 2>/dev/null
[ $? -eq 0 ] && echo "Group found" || echo "Group not found"
 

Further readings:

  • Refer to id, passwd, group man pages

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{ 12 comments… read them below or add one }

1 z0mbix June 27, 2008

don’t forget the “:” after the username otherwise you could end up with this scenario:

$ egrep -i “^vivek” /etc/passwd
vivek:x:1000:1000:Vivek Gite,,,,:/home/vivek:/bin/bash
viveks:x:1001:1001:Vivek Smith,,,,:/home/viveks:/bin/bash

Reply

2 Ramesh | The Geek Stuff June 27, 2008

If you are using NIS do the following:

ypcat passwd | grep vivek

Ramesh
The Geek Stuff

Reply

3 Pedro June 27, 2008

The ‘id’ command should be demonstrated first in this tutorial, as systems using LDAP (other or remote authentication services) will not have users in the local {passwd,group} files.

Also why the uses of egrep when a simple grep will do. Keep it simple for the beginners your aiming at.

Reply

4 davidhi June 27, 2008

You should look at getent rather than grepping the local files. “getent passwd” or “getent group” will provide a unified view of users or groups available, respecting your NSS (Name Service Switch) configuration (which is important when you have additional users or groups via LDAP or NIS).

Reply

5 himadri August 9, 2008

hey Vivek, that was cool..

many of us surely wont care if its grep or egrep ( or fgrep) as long as it does the job and we are taught these wonderful tricks..

Reply

6 New in linux July 15, 2009

Can you please tell me a command to list all of existing user ?

Reply

7 Shahin December 15, 2011

U can try
egrep “*” /etc/passwd
or
egrep “?” /etc/passwd

Reply

8 Vivek Gite July 15, 2009

Try:

cut -d: -f1 /etc/passwd | less

Reply

9 Praba March 17, 2010

Very nice site, I could get, what i want in seconds rather than in minutes

Reply

10 Rob November 14, 2011

`id` comand does not check if groups exist.
`man id`

Print user and group information for the specified USERNAME

the -g flag prints out the primary group id for the user

Reply

11 sohaib December 29, 2011

have you find any solution for that?

Reply

12 sachin November 15, 2011

Hello
Linux Gurus,
Is there a Command to find out user creation date ?

or any other possible ways to find the same.

please help me
Its urgent.

Thanks In Advance

Reply

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