Pass command line argument to bash alias command
Q. How do I pass all command line args to my alias called foo. For example:
alias foo="/path/to/command $@"
However $@ get interpreted when creating the alias instead of during the execution of the alias and escaping the $ doesn't work either. How do I solve this problem?
A. You need to use shell function instead of an alias to get rid of this problem. Define foo as follows:
function foo() { /path/to/command "$@" ;}
Now you can call foo():
foo arg1 arg2 argN
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Tags: alias_command, bash_shell_function, command_line_args, shell_function
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