how can i get rid of spaces in this array

find . -iname ‘*.avi’ -exec mv {} /Some/Where/Else/ \;

This command recursively finds all .avi files in the current directory and moves them to folder /Some/Where/Else. The curly brackets {} are substituted with file name. Consult the man page for more details.

SAVEIFS=$IFS
IFS=$(echo -en "\n\b")
FILES=$1/*
for f in $FILES
do
	#echo	"$f"
	FILENAME="${f//[\?%\+]/_}";
	mv -b --strip-trailing-slashes "$f" "$FILENAME"
done
IFS=$SAVEIFS

replaces ?, % and + with _ (Useful if you copy FAT32 files to linux and back)

The first assigns a newline and a backspace to IFS; the second assigns an empty string.

The first assignment can be done more efficiently with:

IFS=$'\n\b'

IFS=$(echo -en "\n\b")

and

IFS=''

Which do exactly the same (but don’t call sub shell)

find /home/gearond -maxdepth 1 -type f -print0 | xargs -O -I file your-command-on file

In your case:

find . -maxdepth 1 -type f -print0 | xargs -0 -I {} tar -rjvf /tmp/directoryFiles.tar.bz2 {}
tar -tjvf /tmp/directoryFiles.tar.bz2

tar –all the file names– : Cannot stat: No such file or directory

I”ve tried about every expansion or quoting that I can think of for the $direcotryFiles variable.

#!/bin/bash
SAVEIFS=$IFS
IFS=$(echo -en "\n\b")
directoryFiles=""
for file in $( find /home/gearond -maxdepth 1 -type f)
do
  directoryFiles="$directoryFiles\"$file\" "
  #echo $file
done
tar -cf /tmp/directoryFiles.tar.bz2  $directoryFiles
IFS=$SAVEIFS

Gnome for example displays them correctly. Couldn’t manage to create such a file in Gnome. I tested creation in C and Python iirc.

If I do this:

$ for file in $(ls | awk -F. ‘{print $1}’); do sox -S “${file}.m4a” “${file}.ogg”; done

it doesn’t work as I would have expected.

$path is the RC file, and $var is the array variable. BASH variables must be escaped, but PERL
variables must not, and new-line chars have to be added so bash is happy with the string.
First step is to source the RC file, and next get the length of the array.

$list = `. $path; L=\${#${var}[@]}\n for (( i=0; i<\${L}; i++ ));\n do\n echo -n \${${var}[\$i]}\,\n done`;
chop( $list ); # strip the trailing comma

foreach $entry (split(",", $list)) { # Prove that it works
print "entry: '$entry'\n";
}

Here's an example of the bash array that this will parse. Cool. Thanks again for your examples.

ARRAY_VAR=( .bashrc .vimrc "foo bar" .java
.mozilla
.Xdefaults "other file name" )

You don’t need sed or ls; use filename expansion:

grep hello *

“for i in $(find . | sed -e “s/ /?/g) do; ls -l “$i”; done”

That will fail if any filenames contain whitespace.

It is also extremely inefficient to call ls in a loop.

find . | sed -e “s/ /?/g”
ls | sed -e “s/ /?/g”

Then you can do things like greps, for loops, whatever equally well:
grep hello $(ls | sed -e “s/ /?/g”)
for i in $(find . | sed -e “s/ /?/g) do; ls -l “$i”; done

thanks a lot for sharing.

shreyas

Why?

The for command will only see one argument.

Try this:


n=1
for m in "`ls`"
do
echo "$n"
echo "$m"
n=$(( $n + 1 ))
done


You’ll see that it only goes through the loop once.

You don’t need a loop for that, and you don’t need ls:

printf "%s\n" *