Regards

#!/bin/bash
export PGPASSWORD=XXXXX
DIR=/home/ben/backups/psql
[ !$DIR ] && mkdir -p $DIR || :
LIST=$(su postgres -c “psql -lt” |awk ‘{ print $1}’ |grep -vE ‘^-|^List|^Name|template[0|1]‘)
for d in $LIST
do
pg_dump -U postgres $d | gzip -c > $DIR/$d.out.gz
done
export PGPASSWORD=

You can also avoid the number of rows returned with the “-t” option to psql:

psql -lt

Also, to run the script as root from cron, I used su to run the backup as the postgres user. My complete script:

#!/bin/sh
DIR=/backup/pgsql

LIST=$(su - postgres -c "psql -lt" |awk '{ print $1}' |grep -vE '^-|^List|^Name|template[0|1]')

for d in $LIST
do
  su - postgres -c "/usr/bin/pg_dump $d | gzip -c > $DIR/$d.sql.gz"
done

what are the steps i need to follow to achive it.

please help me

Just a few notes:

In the 3rd line
[ ! $DIR ] && mkdir -p $DIR || :
there should be no space character after the exclamation mark!
[ !$DIR ] && mkdir -p $DIR || :
like this it works for me.

@Leopold, thanks for your comment, I had the same problem and your expression for LIST was the solution :)

if you have a list with several databases, the last row is number. For example in my case:
(19 rows)
and after the script
(19

so I propose you generate the LIST with this:
LIST=$(psql -l | awk ‘{ print $1}’ | grep -vE ‘^-|^List|^Name|template[0|1]|^\(‘)

Otherwise, it’s a very nice article.

Thanks.

gunzip all.dbs.out.gz

and then

psql -f all.dbs.out postgres