How do I get the current year in shell script and store in a shell variable called $myyear?
You can use the date command to set or get the current system date and time. You can display the current time/date in the given FORMAT. The FORMAT controls the output. The FORMAT is as follows to get the current year:
%y : Get last two digits of year i.e. 00..99.
%Y : Get year i.e. 1999, 2003 and more.
Syntax
The date command syntax is:
date +"%FORMAT"date +"%y"date +"%Y"
date +"%FORMAT"
date +"%y"
date +"%Y"
Examples
Type the following commands:
date +"%Y"date +"%y"## Store to a shell variable ##mydate=$(date +'%Y')myyear=`date +'%Y'`echo"Year = $mydate"echo"Year = $myyear"
date +"%Y"
date +"%y" ## Store to a shell variable ##
mydate=$(date +'%Y')
myyear=`date +'%Y'`
echo "Year = $mydate"
echo "Year = $myyear"
Sample outputs: Fig.01: date command in action
Posted by: Vivek Gite
The author is the creator of nixCraft and a seasoned sysadmin, DevOps engineer, and a trainer for the Linux operating system/Unix shell scripting. Get the latest tutorials on SysAdmin, Linux/Unix and open source topics via RSS/XML feed or weekly email newsletter.
