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Grep From Files and Display the File Name

How do I grep from a number of files and display the file name only?

When there is more than one file to search it will display file name by default:

grep "word" filename
grep root /etc/*

Sample outputs:

/etc/bash.bashrc:       See "man sudo_root" for details.
/etc/crontab:17 *       * * *   root    cd / && run-parts --report /etc/cron.hourly
/etc/crontab:25 6       * * *   root    test -x /usr/sbin/anacron || ( cd / && run-parts --report /etc/cron.daily )
/etc/crontab:47 6       * * 7   root    test -x /usr/sbin/anacron || ( cd / && run-parts --report /etc/cron.weekly )
/etc/crontab:52 6       1 * *   root    test -x /usr/sbin/anacron || ( cd / && run-parts --report /etc/cron.monthly )
grep: /etc/gshadow: Permission denied
/etc/logrotate.conf:    create 0664 root utmp
/etc/logrotate.conf:    create 0660 root utmp

The first name is file name (e.g., /etc/crontab, /etc/group). The -l option will only print filename if th

grep -l "string" filename
grep -l root /etc/*

Sample outputs:

grep: /etc/at.deny: Permission denied

You can suppress normal output; instead print the name of each input file from which no output would normally have been printed:

grep -L "word" filename
grep -L root /etc/*

Sample outputs:

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{ 13 comments… add one }
  • Josh Keife September 30, 2010, 5:35 pm

    for i in `ls` ; do
    grep -q “whatever” $i && echo $i

    • nixCraft October 1, 2010, 5:42 am

      Why ls? It will fail when you have file names with white spaces. A better way is to use wild cards:

      for i in * ; do
      grep -q “whatever” $i && echo $i
      • lUser February 20, 2011, 8:19 pm

        what about
        grep -rI “whatever” ./ | cut -d: -f1 | sort -u

        nb it will fail on file containing “:” such as some perl man pages but…

        …Or just add some proper form
        for i in `ls` ; do
        grep -q “whatever” “$i” && echo “$i”

  • Josh Keife September 30, 2010, 5:41 pm

    or if you need to search all file and subdirs within a dir you can run the commands above. Just replace `ls` with `find . -type f`.

  • mlathe October 2, 2010, 12:45 am

    Or better yet, use xargs.
    find . -type f | xargs grep html

    If you want to deal with spaces etc…
    find . -type f | xargs -I {} grep -H foo "{}"

    • yoander (sedlav) October 13, 2010, 5:36 pm

      Dealing with space with a shorter form
      find . -type f -print0 | xargs -0 grep foo

  • layman October 19, 2010, 7:46 am

    I agree, find is working great for me.

    find -name *.log -uid 1000

    You can find files only owned by uid. Nifty feature.

  • Becky Gawat March 19, 2012, 6:55 pm

    How do I grep if i am looking for a specfic percentage?
    grep -w “68%-100% /usr/local/stage”

    thanks in advance

  • willywonker May 3, 2012, 8:44 pm

    ls | while read FILE; do echo “$FILE” done;

    This handles whitespace and other nasties nicely.

  • avinash June 7, 2012, 5:22 pm

    how can i grep
    from filename AUZ_CA_EL.txt

    • BrianBlaze November 27, 2012, 5:09 pm

      cat AUZ_CA_EL.txt | grep “CA”

  • Özzesh December 5, 2012, 7:45 am

    how do I know the location and file name form the result that grep shows?
    I use command like cat * | grep
    Now what I need is the location of the file name along withe the grep result.

    Help anyone

  • a January 11, 2014, 10:54 pm

    THX for the “$FILE” solution! Worther than 100 webpages!

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