I have a file called rsnapshot.conf. It has the words “ssh_args=-p 1222”. How do I match and remove (delete) the words “ssh_args=-p 1222” from config file using sed command under Linux or Unix like operating systems?
You can use the the substitute sed command changes all occurrences of the “ssh_args=-p 1222”. The same command can be used to delete the required words.
Sed command syntax to remove words
The syntax is:
sed 's/word-to-find//g' input.file > output.file
Gnu/sed syntax:
sed -i 's/word-to-find//g' input.file
Examples
Type the following command
sed -i 's/ssh_args=-p 1222//g' input.file
sed -i 's/ssh_args=-p 1222//g' /etc/rsnapshot.conf |
sed -i 's/ssh_args=-p 1222//g' input.file
sed -i 's/ssh_args=-p 1222//g' /etc/rsnapshot.conf
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Posted by: Vivek Gite
The author is the creator of nixCraft and a seasoned sysadmin, DevOps engineer, and a trainer for the Linux operating system/Unix shell scripting. Get the latest tutorials on SysAdmin, Linux/Unix and open source topics via RSS/XML feed or weekly email newsletter.
1 comment
what is the command to find a word in a line, then deleting (that line and previous line)
example, I want to search for the word JDK, delete the JDK line and the previous line.
INPUT
————————-
Version 5.1
Version 5.1.1.12
ID BASE
Version 1.4.2
ID JDK
Version 5.1
Version 1.4.2
ID JDK
Version 5.1.1.12
ID ND
OUTPUT
—————————
Version 5.1
Version 5.1.1.12
ID BASE
Version 5.1
Version 5.1.1.12
ID ND