I‘m using the date +’%D_%T’ to store Unix system date and time in a shell variable called $_now:
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_now=”$(date +’%D_%T’)”
echo $_nowOutputs:
01/20/12_16:10:42
I’d like to replace / and : with _. I’m aware of the following sed command:
sed ‘s/\//_/g
> s/:/_/g’ <<<"$_now"Outputs:
01_20_12_16_14_09
How do I specify two pattern within the same sed command to replace | and : with _ so that I can get output as 01_20_12_16_10_42?
You can use any one of the following sed substitute find and replace multiple patterns:
sed -e 's/Find/Replace/g' -e 's/Find/Replace/g' <<<"$var" sed -e 's/Find/Replace/g' -e 's/Find/Replace/g' < inputFile > outputFile out=$(sed -e 's/Find/Replace/g' -e 's/Find/Replace/g' <<<"$var") |
OR
sed 's/Find/Replace/g;s/Find/Replace/g' <<<"$var" sed -e 's/Find/Replace/g;s/Find/Replace/g' <<<"$var" sed -e 's/Find/Replace/g;s/Find/Replace/g' < inputFile > outputFile out=$(sed -e 's/Find/Replace/g;s/Find/Replace/g' <<<"$var") |
Examples: Find And Replace Sed Substitute Using a Singe Command Line
_now="$(sed -e 's/\//_/g;s/:/_/g' <<<$(date +'%D_%T'))" echo $_now |
Sample outputs:
01_20_12_16_22_21
Here is another version:
_now=$(sed 's/[\/:]/_/g' <<<$(date +'%D_%T')) echo "$_now" |
Sample outputs:
01_20_12_16_24_42
5 comment
Alternatively, one could tell `date` the desired format, like date +%Y-%m-%d-%H-%M
Just do:
now=`date +”%m_%d_%y_%H_%M_%S”`
echo $now
Man was showing sed not date command…
I have a not well experience with awk and sed. if any find the solution?
I have a two variable like..
$var1=a-45afd4
a-fdfgh3 ##here two word in one column and may you can say in row
$var2=a-45afd4 string1 string2 string3 string4
a-fdfgh3 string1 string2 string3 string4
a-hfdj3e string1 string2 string3 string4
a-jkkl3l string1 string2 string3 string4
i want to find $var1 data in $var2 and the output should be
Example: a-45afd4 string1 string2 string3 string4
a-fdfgh3 string1 string2 string3 string4
##rest all column row should not come
What is the output of “date -u +%V`uname`|sha512sum|sed ‘s/\W//g'”?