Linux / Unix: Sed Substitute Multiple Patterns [ Find & Replace ]

I‘m using the date +’%D_%T’ to store Unix system date and time in a shell variable called $_now:

_now=”$(date +’%D_%T’)”
echo $_now

Outputs:
01/20/12_16:10:42

I’d like to replace / and : with _. I’m aware of the following sed command:

sed ‘s/\//_/g
> s/:/_/g’

Outputs:
01_20_12_16_14_09

How do I specify two pattern within the same sed command to replace | and : with _ so that I can get output as 01_20_12_16_10_42?

You can use any one of the following sed substitute find and replace multiple patterns:

sed -e 's/Find/Replace/g' -e 's/Find/Replace/g' <<<"$var"
sed -e 's/Find/Replace/g' -e 's/Find/Replace/g' < inputFile > outputFile
out=$(sed -e 's/Find/Replace/g' -e 's/Find/Replace/g' <<<"$var")

OR

sed 's/Find/Replace/g;s/Find/Replace/g' <<<"$var"
sed -e 's/Find/Replace/g;s/Find/Replace/g' <<<"$var"
sed -e 's/Find/Replace/g;s/Find/Replace/g' < inputFile > outputFile
out=$(sed -e 's/Find/Replace/g;s/Find/Replace/g' <<<"$var")

Examples: Find And Replace Sed Substitute Using a Singe Command Line

_now="$(sed -e 's/\//_/g;s/:/_/g' <<<$(date +'%D_%T'))"
echo $_now

Sample outputs:

01_20_12_16_22_21

Here is another version:

_now=$(sed 's/[\/:]/_/g' <<<$(date +'%D_%T'))
echo "$_now"

Sample outputs:

01_20_12_16_24_42