There are many ways to display a text file in a shell script. You can simply use the cat command and display back output on screen. Another option is to read a text file line by line and display back the output. In some cases you may need to store output to a variable and later display back on screen.
Task: Display output using the cat command
Following sample script displays contents of a file called /tmp/input.txt:
#!/bin/bash FILE="/tmp/input.txt" echo "*** File - $FILE contents ***" cat $FILE |
Task: Store a file output in a variable
Following sample script displays nameserver IPs:
#!/bin/bash FILE="/etc/resolv.conf" OUT=$(awk '{ print $2 }' $FILE) echo "*** Nameserver IP ***" for ip in $OUT do echo $ip done |
Task: Read a text file line-by-line
See our previous tutorial for more information:
- Linux/ UNIX: Read a File Line By Line
- Linux / Unix AWK: Read a Text File
- HowTo: Bash For While Loop Through File Contents Script
- Ksh Read a File Line By Line ( UNIX Scripting )
6 comment
2nd option is good. If file is large, one can modify the script a bit to serve the purpose.
How to display certain part of a file? For example, I have a file myFile.Java and I would like to display the contents between lines 30-40. How to do that in linux? with cat?
Thanks,
I have 1 more Que.
i want a shell script for identify mentioned string is file or directory if its a directory then display the contests of the same and if this is file show the content of file
cat $FILE
echo “$(<$FILE)"
tee <$FILE
Sir,
I am a beginner in Linux /Unix and I want answer to the following question.
Q. Write a shell script in Linux /Unix that accepts a text file as input and prints the number of words in the file which have at least one vowel as output.
Sir,
Please give me answer as soon as possible.
Thanks