How to repeat a character ‘n’ times in Bash

Let us say you want to repeat a character such as ‘-‘ OR ‘=‘ multiple times while writing bash script. Please note that I needed a quick script to work on Linux, macOS, and FreeBSD server to repeat a string/character n times. One simple way to to repeat a string or character n times is simple use the echo command/printf command as follows:
echo '------------------------------------'
printf '%s\n' '------------------------------------'

But, there must be a better way. For instance, here are classic Perl and Python examples that repeat ‘-‘ 80 times:

perl -E 'say "-" x 80'

Python one-liner:

python -c 'print "-" * 80'

How to repeat a character ‘n’ times in Bash

Let us try this example Linux and Unix Bash function to repeat a string/character ‘n’ times with help of bash for loop as follows:

# Repeat given char 80 times using shell function
	for i in {1..90}; do echo -n "$1"; done

Then all I have to do is call repeat() as follows:

repeat '-'
repeat '='
repeat '~'; echo -e '\nHEAD 1\t\tHead 2\t\tHead 3\t\t\t\tHead 4'; repeat '~'; echo

My solution is simple and friendly. It solved my problem. Yet now I am getting greedy. I wanted to see if I could use printf/echo and replicate the Perl/Python one-liner experience.

Repeating a character or string n times using printf

The printf is a shell built-in and external /bin/printf, used to format and prints ARGUMENTS. The syntax is:

printf 'FORMAT' var
printf '%s\n' 'Hello World'
printf -- '-%.0s' 1 2 3 4 5
printf -- '-%.0s' {1..5}
printf -- '-%.0s' {1..80}


  • The double dash “--” means “end of command line flags.” Since I need to print -, the double dash (--) tells printf command not to try to parse what comes after command line options.
  • Bash expands {1..5}. For example, echo {1..5}, prints 1 2 3 4 5. So
    printf -- '-%.0s\n' {1..5}
    printf -- '-%.0s\n' 1 2 3 4 5
  • The -%0s print single ‘-‘ given 5 times.
  • You can remove double dash (--) when not printing '-‘. For instance:
    printf '~%.0s\n' {1..80}

Closing note

I ended up using the following as I needed to run script on both macOS/BSD and Linux:

# Repeat given char N times using shell function
	local start=1
	local end=${1:-80}
	local str="${2:-=}"
	local range=$(seq $start $end)
	for i in $range ; do echo -n "${str}"; done

Then I run it as follows:

repeat 80 '-'; echo
repeat 40 '='; echo
# print Hello 5 times 
repeat 5 'Hello'; echo

I am sure someone could come up with awk, sed, echo/printf and other versions too. But, for now, I am satisfied with what I got. As usual, check man pages:
man bash
help printf
man seq

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🐧 10 comments so far... add one

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10 comments… add one
  • Harshvardhan Gupta Jun 4, 2021 @ 11:25

    You can use powershell core on Linux and write: “*” * 25

  • Bit Twiddler Jun 5, 2021 @ 8:47

    Nice! I’d previously used things like:

    head -c 80 ​< /dev/zero | tr '\0' '.'

    • Anonymous Jun 6, 2021 @ 19:48

      Wow. Never thought of that.

  • Cüneyt Egin Jun 5, 2021 @ 18:44

    How about:
    seq -s_ 200|tr -d '[:digit:]'
    to print a line with 200 underscores…

  • Dumitru Uzun Jun 6, 2021 @ 5:40

    There is a small typo in the last line of the last ‘repeat()’:
    It should be “$str” instead of “$2”

  • Rehman Jun 6, 2021 @ 12:25

    As usual, awesome post for Bash lovers like me.

    • Didi Jun 6, 2021 @ 19:48

      +1 from me too.

  • Bruce M Jun 9, 2021 @ 11:00
    # repeat times char
    if test $# -ne 2 ; then
        echo 1>&2 usage: $(basename $0) times char
        exit 1
    yes "$2" | head -n "$1" | tr -d '\n'

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