Bash History: Correct / Repeat The Last Command With a Substitution

Posted on in Categories , , last updated February 23, 2016

I often type the wrong command as follows under Linux bash shell:

rsync -av dir1 [email protected]:/path/to/dir1


cp -av file1*.txt file2*.txt /path/to/dest

I need to correct those command as follows:

rsync -av dir5 [email protected]:/path/to/dir1
cp -av delta1*.txt delta2*.txt /path/to/dest

How do I replace dir1 with dir5 or file with delta and repeat the last command under bash shell?

Bash: Get The Last Argument Passed to a Shell Script

Posted on in Categories last updated June 26, 2012

I‘m writing a bash wrapper script that will pass arguments to the command. I need to find out the last argument if I call the wrapper as follows:

./wrapper -a -b –longarg=foo thisfilename.txt
./wrapper -a -b thisfilename.txt
./wrapper -a –next=true thisfilename.txt

=> $@ is all of them.
=> $0 is script name.
=> $1 is first arg.

I want thisfilename.txt stored in a shell variable called $last. How do I find the last argument passed to a shell script written in bash or ksh under Unix like operating systems?

Linux / Unix: Sed Substitute Multiple Patterns [ Find & Replace ]

Posted on in Categories last updated January 20, 2012

I‘m using the date +’%D_%T’ to store Unix system date and time in a shell variable called $_now:

_now=”$(date +’%D_%T’)”
echo $_now


I’d like to replace / and : with _. I’m aware of the following sed command:

sed ‘s/\//_/g
> s/:/_/g’ <<<"$_now"


How do I specify two pattern within the same sed command to replace | and : with _ so that I can get output as 01_20_12_16_10_42?