ksh

I‘m writing a bash wrapper script that will pass arguments to the command. I need to find out the last argument if I call the wrapper as follows:

./wrapper -a -b –longarg=foo thisfilename.txt
./wrapper -a -b thisfilename.txt
./wrapper -a –next=true thisfilename.txt

Where,
=> $@ is all of them.
=> $0 is script name.
=> $1 is first arg.

I want thisfilename.txt stored in a shell variable called $last. How do I find the last argument passed to a shell script written in bash or ksh under Unix like operating systems?
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I‘m using a Mac OS X and combination of ssh-agent+ssh-add to adds RSA or DSA identities to the authentication agent. ssh-agent provides me a secure way of storing the private key. However, I’d like to expire identities added to the agent within half an hour. How do I set lifetime of identities added to the agent under Unix / Linux / BSD / Apple OS X operating systems?
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I have a file of that looks as follows:

foo bar
tom jerry
UNIX Linux

Each word and/or Linux is a different length. How do strip or remove the last character from each line using bash or ksh shell only on a Linux or Unix-like systems?[donotprint]

Tutorial details
Difficulty Easy (rss)
Root privileges No
Requirements None
Time 2m
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