shell

I would like to skip first two or three fields at the the beginning of a line and print the rest of line. Consider the following input:
    This is a test
    Giving back more than we take

I want my input file with the following output:
    a test
    more than we take

How do I printing lines from the nth field using awk under UNIX or Linux operating systems?
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I have a file of that looks as follows:

foo bar
tom jerry
UNIX Linux

Each word and/or Linux is a different length. How do strip or remove the last character from each line using bash or ksh shell only on a Linux or Unix-like systems?[donotprint]

Tutorial details
Difficulty level Easy
Root privileges No
Requirements None
Est. reading time 2m
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All UNIX / Linux applications linked against the OpenSSL libraries can verify certificates signed by a recognized certificate authority (CA). How do I verify SSL certificates using OpenSSL command line toolkit itself under UNIX like operating systems without using third party websites?
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