Each bash shell function has the following set of shell variables: [a] All function parameters or arguments can be accessed via $1, $2, $3,..., $N.
| Tutorial details | |
|---|---|
| Difficulty level | Easy |
| Root privileges | No |
| Requirements | Bash |
| Est. reading time | 1 minute |
Example
Create a shell script as follows:
#!/bin/bash # Purpose: Demo bash function # Author: nixCraft # ----------------------------- ## Define a function called foo() foo(){ echo "Function name: ${FUNCNAME}" echo "The number of positional parameter : $#" echo "All parameters or arguments passed to the function: '$@'" echo } ## Call or invoke the function ## ## Pass the parameters or arguments ## foo nixCraft foo 1 2 3 4 5 foo "this" "is" "a" "test"
Run it as follows:
$ chmod +x script.name.here
$ ./script.name.here
Sample outputs:
Fig.01: Bash function displaying number of arguments passed to foo()
See also
- Chapter 9: Functions from the Linux shell scripting wiki.
- man page – bash
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Try using the special variable ${#}.
function foo {
echo “N. of Args: ${#}”
}
$ foo a b c
3
Hi,
Using ${#} will give the number of arguments but let’s say someone wants to get the name of arguments and value of argument. How one can do that?
Are you passing named arg? Like