awk / cut: Skip First Two Fields and Print the Rest of Line

Old solution

My old solution to skip first two fileds and print the rest of line:
echo 'This is a test' | awk '{print substr($0, index($0,$3))}'
You can also use substr:
substr(s, i [, n])
It return the at most n-character substring of s starting at i. If n is omitted, use the rest of s. So:
awk '{print substr($0, index($0,$3))}' <<< 'This is a test'
You can also use the cut command:
echo 'This is a test' | cut -d ' ' -f3-
cut -d ' ' -f3- <<<'This is a test'
Finally, process the file using bash while loop:

#!/bin/bash
_input="/path/to/file.name.txt"
while IFS= read -r line
do
    cut -d ' ' -f3- <<<"$line"
    ### same stuff with awk ###
    ### awk '{print substr($0, index($0,$3))}' <<< "$line" ###
done < "${_input}"

How to create HTML table using awk

Say you have data as follows in a text file called data.txt:

-v	Show version
-d	Set delta value
-o	Set output file name
-i	Set input filename for this command

To create html table code run:

awk 'BEGIN{ print "<table>"}
{ printf "<tr><td>%s</td><td>", $1; $1=""; print $0 "</td></tr>"}
END{ print "</table>"}' data.txt

Sample session:

Please note that you can also use Perl, Python or other shell text processing commands to do the same thing.