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Bash source Command: $0 Can Not Determine Its Own Location

The source command read and execute commands from a file. My parent.sh script source a script called child.sh. But, child.sh script can not determine it’s own location using $0. By default, $0 gives parent script location. How do I find out a script that is sourced at the command line can determine it’s own location? My sample script:

#!/bin/bash
# /var/www/html/java/tasks/child.sh 
_me="$0"
 
 
# I want /var/www/html/java/tasks in _currentdir 
_currentdir="${_me%/*}"
echo "${_currentdir}"

When I run from parent.sh:

source child.sh

OR

source /var/www/html/java/tasks/child.sh

The $_currentdir is set to be the directory where parent.sh lives which is in /root/scripts/java/helper or . (current) directory. How do I fix this problem?

You need to use an array variable called BASH_SOURCE whose members are the source filenames corresponding to the elements in the FUNCNAME array variable. This variable available since bash version 3.x+. To fix your problem, fix child.sh script as follows:

#!/bin/bash
# /var/www/html/java/tasks/child.sh 
# get child.sh location using the following array
 
###################################################################
# *** Warning it will only work with bash 3.0 and above only **** #
###################################################################
_me="${BASH_SOURCE[0]}"
 
# Fixed 
_currentdir="${_me%/*}"
 
echo "${_currentdir}"

Test it as follows:

cd /tmp
pwd
source /var/www/html/java/tasks/child.sh

Sample outputs:

/var/www/html/java/tasks

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{ 1 comment… add one }
  • reņģis May 11, 2012, 7:41 am

    “Its location” not “it’s location”.

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