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Shell scripting and brace expansion

Expansion is performed on the command line after it has been split into words. Brace expansion is a mechanism by which arbitrary strings may be generated. A sequence expression takes the form {x..y}, where x and y are either integers or single characters. Simple bash brace expansion example:

$ echo F{1,2,3,4,5}
F1 F2 F3 F4 F5

It works with almost any command:

$ mkdir -p /home/project/{sales,purchase,reports}

It is funny but some time you can stuck in shell scripting very badly and you do not understand what is going on … For example I need to expand hostnames using host1.my.com,host2.my.com,…host10.my.com then I can use brace expansion at shell prompt as follows:

$ echo host{1..5}.my.com
host1.my.com host2.my.com host3.my.com host4.my.com host5.my.com

Now try it in a shell script:

for i in $HOSTS
ping $i
# rest of logic

And then executed script by typing command:

$ ./myscript host{1..5}.my.com 

It will not expand to host1.my.com, host2.my.com….. :/? It took me more than two hours, finally while chatting with my friend he told me to replace HOSTS=”$1″ with HOSTS=”$@”. Bingo it worked!
According to bash man page,”A sequence expression takes the form {x..y}, where x and y are either integers or single characters. When integers are supplied, the expression expands to each number between x and y, inclusive. When characters are supplied, the expression expands to each character lexicographically between x and y, inclusive. Note that both x and y must be of the same type”. $@ is a special shell variable which. expands to the positional parameters, starting from one. When the expansion occurs within double quotes, each parameter expands to a separate word. I must admit I need to master shell shell scripting skills ;)

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{ 2 comments… add one }
  • riscphree December 18, 2005, 3:10 pm

    albeit simple, thats pretty sweet. I didnt know how to do that :D

  • abhishek March 7, 2013, 5:54 am

    I am trying to understand a shell script demo1.sh
    this is used to count the number of files in a directory

    declare -a args=( “$@” )
    echo ${#args[@]} # count the elements of the array args

    bash demo1.sh *pdf will give you the correct number of pdf files.

    Can you explain how does this work or how is it getting expanded specially in first line
    (“$@”) why the bracket () is used here and in second line args[@] what does this gets expanded to?

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